2. Method
Figure 1 is a schematic of the presented model in its initial state. The circuit employs two same-output voltage sources V and two identical loads which are not pure electrical loads, as they must output an energy of
Eout per electron. As shown in the figure, this circuit system is highly symmetric. The voltage
V is expressed in terms of the electric potential
φe as follows:
Note that
α,
β,
α’ and
β’ in
Figure 1 are the names of taps.
The principle of the model is shown in
Figure 2, which (unlike
Figure 1) includes a pair of stray capacitors C
0 embedded in a vacuum. At initial time
t = 0, the stray condensers C
0 are shorted. (Note that a condenser is generally shorted at the initial state due to its voltage–current characteristic.) At some transition time
t =
tc, which is essentially equal to the time constant
τc–R (the product of the capacitance (
C0) and load resistance (
R) of the load), there is a transient current (
i) and an emergent electric potential (
φ) defined as follows:
where e is the electron charge.
At time (
tc), the following condition must be satisfied:
where all electrons penetrate the lattices of the substance. Note that resistance (
R) is the internal ones of the loads in
Figure 2. The right-hand side of this inequality indirectly defines the energy of the voltage source V. Thus, we can rewrite Eq. (3) as:
where kB and T denote the Boltzmann constant and temperature, respectively. In most situations, the temperature is the room temperature (i.e.) but eq. (4) implies that Joule heating is ineffective.
As discussed later, the term equals the kinetic energy (ε).
When the above condition is satisfied, the energies stored in the condensers are discharged. Under the energy-conservation law, energy interchange between the paired up-condenser and down-condenser in
Figure 2 induces a constant current (
IE’) along the C
0-load-to-C
0-load loop. Because the condensers C
0 are embedded in a vacuum and cannot be touched, a divergent current (
IE’) is generated. Note that if the inequality is not satisfied, the condensers never discharge their current but if the inequality is satisfied, the voltage sources V momentary operate until the condensers begin discharging at time (
tc) and are dormant thereafter, thereby generating energy.
We now discuss the emergent electric potential (φ) after steady-state.
In the vicinity of tap
α or
β at
t =
tc, we have:
and
where
Ee and
Ec0 denote the ohmic and condenser-associated electric fields, respectively.
Note that the vector (ds) aligns along the direction of (IE’).
Given that the condenser discharges the current, we have:
However, in the vicinity of a tap, we have:
In the steady-state where (
Eout) is nonzero, the electric potential becomes:
This emergent electric potential (
φ) is demonstrated in
Figure 3.
Let us introduce a wave function contributing to the electron motion.
The general form of the Hamiltonian is:
where the first and second terms describe the center-of-mass motion and the net electron–electron interaction, respectively. As the emergent energy (
eφ) is sufficiently large, the following assumption holds:
This condition guarantees the one-particle picture. If Eq. (4) is satisfied, the Hamiltonian and electron motion can be approximated as one-dimensional because lattice disturbance and electron scattering phenomena are absent.
From an alternative perspective, we can assume a uniform electrical potential (φ) at tap α or β, implying that each electron has approximately the same electrical potential (φ). As (φ) cannot coexist with a Coulomb interaction potential (φM), the Hamiltonian (Heff) is sufficiently small. Moreover, whether the potential (φ) is macroscopic or microscopic cannot be discerned and the absence of net heating implies no Fermi statistics, which includes a temperature, even at local positions.
The Hamiltonian at tap
α is:
where m denotes the mass of an electron.
As energy is conserved, we have:
where k is the wavenumber.
Here, we associate the positive and negative values of (
kα) with up-spin and down-spin, respectively. Thus, the wavefunctions are
respectively. Note that (
j) is the imaginary unit. Similarly to tap
α, tap
β satisfies the following Hamiltonian:
By energy conservation, we have:
Here, positive and negative (kβ) denote down-spin and up-spin, respectively. Note that the potential in the Hamiltonians is the Coulomb force. That is, the taps with positive and negative potentials exert an attractive force (–F) and a repulsive force (+F) on the electron, respectively. These forces are effective only when the electron motions form in negligible lattice disturbance (i.e., negligible Joule heating). Note that as these forces concern only the center-of-mass motion, inter-electron Coulomb interactions can be ignored as previously discussed.
In summary, the wave functions of
α and
β are dual; that is:
The first and second terms of the above equation correspond to the left and right sides of the circuit in
Figure 3, respectively. The first and second terms are considered to be related through the Einstein–Podolosky–Rosen correlation [
20].
Here, we consider only the first term of Eq. (27).
The uncertainty relation gives
Because the phase (θ) is constant, the uncertainty
becomes infinite, defying the classical physical motion of an electron from one tap to the other. The wavefunction of the left part of the circuit is:
The probability density (
jE) of the flow:
Herein, we separately consider paired LEDs or paired DC motors as the loads.
- 1)
DC motor loads
From the normalization condition:
where λ is the wavelength of an electron.
The wavenumber (
k) is defined as:
The wavenumber is also derived as:
from which the flow probability density (
jE) is obtained as:
To obtain the net current density [A/m
2], we multiply Eq. (37) by the electronic charge (
e):
Here, the area (
Si) is considered as a unit cell; for example,
Importantly, the net observed current
is then derived as:
- 2)
LED loads
Under the normalization condition:
but here we consider the momentum of a photon with wavenumber [
21]:
The photon imparts its momentum to an electron or hole; that is:
Similarly to the DC motor, the LED loads obtain a net current density of:
As the net current is contributed by an electron and a hole, we have:
Within the area (
Si) of a unit cell, e.g.,
Next, the DC-motor loads must satisfy two conditions. Let us consider these conditions:
The general motion equation of a motor is [
22] as follows:
where Ra [Ω], Ia [A], L [H], and E [V] denote the inner resistance, working current, inductance, and reverse electromotive force, respectively.
Let us first obtain the general solution from Eq. (50). To obtain this solution, setting the nonhomogeneous term
to zero, the general solution is immediately obtained as:
At
t = 0 when all currents flow into the condensers C
0, the initial current in the motor is zero; that is:
Moreover, the special solution of Eq. (50) is derived by:
Thus, by the substitution to eq. (50),
and thus the net solution, i.e., the sum of the general solution and the special solution, is:
The transient equation of the motors in our system is then given by:
In this equation, the proportionality constant (kE) depends on the magnetic flux, and (Ωm) is the rotational velocity.
The current (Ia) is considered as the constant current under zero load (Ia0).
Under the working condition:
of our system, the motor must satisfy:
where Ωm0 is the speed under zero load.
We now derive the second mandatory condition of the motors. To this end, we discuss the net voltage of the motor. At
t = tc when the voltages between the condenser and voltage source are canceled,
Va = 0. From Eq. (56), we then have:
meaning that (Ia0) is an induced loop current not induced by the voltage source.
At
when the current is discharged by the condensers C
0,
where Vc is the discharging voltage of the condenser.
As discussed below, the above equation neglects the Joule heating term.
The motor voltage becomes the superposition of (
Ec) and (
E), as shown in
Figure 4. Thus, the net energy of an electron is:
Based on the abovementioned discussion, the motors must satisfy:
where
and
denote the impedance input to the other motor during the current discharge, which may include the internal resistance of the voltage source V, and
is the time constant of
. The left side of Eq. (63) is the coil discharge of the motor, but because the motors are paired in our system, they reciprocally provide and receive energy. Provided that the second condition above is satisfied, the Joule heating term is absent and the motor receives a relatively large input voltage, as discussed in the Results section. Moreover, we will show that because the voltage of a motor is:
implying that the voltage sources V are nonoperational, the paired motors repetitively store and discharge energy.
The macroscopic current (
Ia0) can coexist with the microscopic current
in the load but the two currents are not superposed, so an additive current does not appear. Thus, if a current meter is connected in series with a motor, it records either the current (
Ia0) or the current
at each moment, presenting widely fluctuating currents to the experimental observer. Accordingly, we set a detour for the current
in the system with paired DC motors (
Figure 5). In the Results section, we will discuss the importance of:
Here, let us introduce the output electric power (
W). The incremental value of (
W) is
Given the voltage–current characteristics Eqs. (40) and (49), the derivative derived from these characteristics inevitably provides an electric resistance (
R0). Thus, we have
Given
, we obtain
Integrating both sides of Eq. (70) gives
Provided that the conditions in our system are satisfied, Eq. (71) is not a Joule-heating expression. The absence of Joule heating can be explained by the dead voltage sources, as frequently described in this paper. The voltage sources are only temporarily active in the vicinity of the initial time.