Submitted:
08 February 2024
Posted:
13 February 2024
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Abstract
Keywords:
1. Introduction

2. Binary oppositions in genetic alphabets, Gray-type matrices, and Karnaugh maps
- 1)
- two of these nucleotides are purines (A and G), and the other two (C and T) are pyrimidines, which gives the representation C = T = 0, A = G = 1;
- 2)
- two of these nucleotides are keto molecules (T and G), and the other two (C and A) are amino molecules, which gives the representation C = A = 0, T = G = 1.


3. Genetic code degeneracy and genetic Gray-type matrices


3.1. Analysis of the genetic Gray-type matrix for 16 duplets









3.2. Analysis of the genetic Gray-type matrix for 64 triplets


011, 010, 110, 111, 101, 100, 000, 001;
010, 110, 111, 101, 100, 000, 001, 011;
110, 111, 101, 100, 000, 001, 011, 010;
111, 101, 100, 000, 001, 011, 010, 110;
101, 100, 000, 001, 011, 010, 110, 111;
100, 000, 001, 011, 010, 110, 111, 101



4. Interrelation between the Hilbert curve and Gray codes for using in genetic studies


5. Gray codes for modeling genetic structures and inherited cyclic phenomena. Cyclic biocomputing

- -
- chromosome crossing over;
- -
- biological colonies based on cyclic n-bit Gray codes using concatenation operations,
- -
- complementary replication, fragmentation, etc.;
- -
- amino acid sequences of proteins and their “life-death” cycles, including the breakdown of proteins into amino acids and their rebirth; and etc.



6. Genetic Hadamard matrices, Walsh functions, and Gray codes
- -
- Firstly, at the transition from DNA to RNA only one letter T is replaced by U (uracil), and the other three letters are not changed;
- -
- Secondly, in the genetic alphabet, only the molecule T (and also the molecule U in RNA) has not the important amino-group NH2 in contrast to the molecules A, C, and G (Figure 6.1).





7. Gray codes, dyadic clock, and the sequency theory by Harmuth
8. Universal stochastic rules of genomic DNAs, binary-genomic numbers, and complementarity operation
- -
- first, a studied BG-number is represented as a sequence of single characters 0-1-1-1-0-0-... and the percentages %0 and %1 are calculated in it;
- -
- second, it is represented as a sequence of duplets 01-11-00-10-... and the percentages of each type of binary duplets %00, %01, %10, %11 are calculated;
- -
- after this, similarly, the same BG-number is represented as a sequence of binary triplets, tetraplets, pentaplets, ..., with calculation of the percentages of the corresponding types of n-plets each time.




| % | X | СУММА | ∑ | ∑-X |
| %0 = | 0,4997 | %00+%01= | 0,4998 | 0,0001 |
| %1 = | 0,5003 | %10+%11= | 0,5002 | -0,0001 |
| %00 = | 0,2807 | %000+%001= | 0,2807 | 0,0000 |
| %01= | 0,2191 | %010+%011= | 0,2191 | 0,0000 |
| %10 = | 0,219 | %100+%101= | 0,219 | 0,0001 |
| %11= | 0,2812 | %110+%111= | 0,2812 | -0,0001 |
| %000 = | 0,1646 | %0000+%0001= | 0,1646 | 0,0000 |
| %001 = | 0,1161 | %0010+%0011= | 0,116 | -0,0001 |
| %010 = | 0,1031 | %0100+%0101= | 0,1031 | 0,0000 |
| %011= | 0,116 | %0110+%0111= | 0,116 | 0,0000 |
| %100 = | 0,116 | %1000+%1001= | 0,1159 | -0,0001 |
| %101= | 0,1031 | %1010+%1011= | 0,1031 | 0,0000 |
| %110 = | 0,1159 | %1100+%1101= | 0,116 | 0,0001 |
| %111= | 0,1652 | %1110+%1111= | 0,1651 | -0,0001 |
| %0000 = | 0,0977 | %00000+%00001= | 0,0977 | 0,0000 |
| %0001= | 0,0669 | %00010+%00011= | 0,0669 | 0,0000 |
| %0010= | 0,0556 | %00100+%00101= | 0,0556 | 0,0000 |
| %0011= | 0,0604 | %00110+%00111= | 0,0604 | 0,0000 |
| %0100 = | 0,0555 | %01000+%01001= | 0,0555 | 0,0000 |
| %0101= | 0,0476 | %01010+%01011= | 0,0476 | 0,0000 |
| %0110 = | 0,049 | %01100+%01101= | 0,049 | 0,0000 |
| %0111= | 0,067 | %01110+%01111= | 0,067 | 0,0000 |
| %1000 = | 0,0669 | %10000+%10001= | 0,0669 | 0,0000 |
| %1001= | 0,049 | %10010+%10011= | 0,0491 | 0,0001 |
| %1010 = | 0,0475 | %10100+%10101= | 0,0475 | 0,0000 |
| %1011= | 0,0556 | %10110+10111= | 0,0556 | 0,0000 |
| %1100 = | 0,0605 | %11000+%11001= | 0,0606 | 0,0001 |
| %1101= | 0,0555 | %11010+%11011= | 0,0555 | 0,0000 |
| %1110 = | 0,0669 | %11100+%11101= | 0,0669 | 0,0000 |
| %1111= | 0,0982 | %11110+%11111= | 0,0982 | 0,0000 |

Some concluding remarks.
Appendix A. Regarding Gray codes

- -
- any pair of adjacent codewords in this cyclic sequence of 8 codewords is a separate cyclic subsequence (for example, 000, 001 or 010, 110);
- -
- the first quadruple of codewords (000, 001, 011, 010) is a cyclic subsequence with unit Hamming distance between adjacent terms. The same is true for the subsequence of final four codewords (110, 111, 101, 100);
- -
- symmetrical cropping of the same number of codewords from both ends of a Gray codeword sequence generates a cyclic subsequence (for example, by removing one term from both ends of the sequence under consideration, we obtain a cyclic subsequence 001, 011, 010, 110, 111, 101, and by removing 2 terms from both ends, we obtain another cyclic subsequence 011, 010, 110, 111).
Appendix B. Regarding dyadic-shift decompositions of matrices

Acknowledgments
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