Submitted:
27 May 2023
Posted:
30 May 2023
You are already at the latest version
Abstract
Keywords:
1. Introduction
2. Preliminaries
2.1. Submodular Partition Functions
2.2. Loose P-Tangle
- (P1) ∅ ∈ T, {e} ∈ T, for all e ∈ X such that the partition [{e}, X\{e}] belongs to Pk[ψ].
- (P2) If A1, A2, . . ., Ap ∈ T , Ci ⊆ Ai for i = 1, . . ., p, [C1, . . ., Cp, X\(C1 ∪ . . . ∪ Cp)] ∈ Pk[ψ], then C1 ∪ . . . ∪ Cp ∈ T.
- (P3) X ∉ T.
2.3. Filter of partitions
- (F1) For all e ∈ X, if the partition [{e}, X\{e}] belongs to Pk[ψ], then {e}∉ F,
- (F2) If A1 ∈ F, A1 ⊆ A2, [A2, X\(A2)] ∈ Pk[ψ], then A2 ∈ F,
- (F3) If A1, A2, . . .,Ai ∈ F for i = 1, . . ., p, [X\A1, . . .,X\ Ap, X\(X\A1 ∪ . . . ∪ X\Ap)] ∈ Pk[ψ], then A1 ∩ ... ∩ Ap ∈ F,
- (F4) ∅ ∉ F.
- (SF2) If A ∈ F, B ∈ Σ, A ⊆ B, then B ∈ F,
- (SF3) If A₁, A₂, A₃, ... ∈ F, then A1 ∩ ... ∩ Ap ∈ F
- (SF4) ∅ ∉ F.
3. Cryptomorphism between Loose tangle of partitions and Filter of partitions
- -
- First, we'll show that if T is a loose Pk[ψ]-tangle, then F = {A | X\A ∈ T } is a Pk[ψ]-(non-principal) filter.
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- Secondly, we'll show that if F is a Pk[ψ]-( (non-principal) filter, then T = {A | X\A ∈ F} is a loose Pk[ψ]-tangle.
4. Future tasks
Acknowledgements
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