Submitted:
23 November 2025
Posted:
24 November 2025
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Abstract
Keywords:
MSC: 40A05; 46A45; 26A03; 05C20
1. Introduction
1.1. Real Valued Sequences
1.2. Motivation
1.3. Study Outline
2. Preliminaries
2.1. Set-Theoretic Foundations
- 1.
- The sequence is non-decreasing and is non-increasing.
- 2.
- For every :
- 3.
-
The limitsalways exist in .
- 4.
- We always have the inequality
- (i)
- If the (finite) limit exists and is equal to , then
- (ii)
- Conversely, if , then converges to L, that is,
- (iii)
- If , then the sequence does not converge in ; in this case is either divergent to or oscillatory between at least two distinct cluster values.
2.2. Linear-Algebraic Foundations
- (i)
- The elements of B are linearly independent.
- (ii)
- Every element can be written as a finite linear combination of elements of B; that is,for some , scalars , and distinct .
- If such a set B exists, the cardinality is called the (Hamel) dimension of X.
- the algebraic viewpoint, where has a Hamel basis of cardinality , and
- the analytic viewpoint, where familiar sequence spaces admit countable Schauder bases describing their elements through convergent series.
- Our classification of into seven macroscale blocks will be constructive and finitary in spirit, and will be independent of any particular choice of Hamel or Schauder basis.
2.3. Special Sequences
- (A)
- has and finite;
- (B)
- has finite ;
- (C)
- has finite and ;
- (D)
- has and .
- Here and denote, respectively, the lim inf and lim sup of the corresponding sequence.
- (A–pattern). Define c byThen for all k and for . Hence b has a subsequence equal to and infinitely many zeros, so
- (B–pattern). Split S into two infinite subsequences, for instanceDefine b byand then set whenever , and when . By construction b takes the values infinitely often (and 0 possibly as well), henceso and are finite with .
- (C–pattern). Choose any infinite subsequence and defineand again put when , when . Then while for infinitely many n, so
- (D–pattern). Using the same partition as above, defineand set for , when . Then b has subsequences and , hence
3. Main Results
3.1. Partition of with Scenario Classification & Examples
3.2. The Relationship between the Blocks
3.2.1. Macroscale
- (i)
-
Target G ().Then is constant, hence in G.
- (ii)
-
Target F ().Clearly , so .
- (iii)
- Target E ().so and .
- (iv)
-
Target D ().Along even indices the sequence tends to ; along odd indices it tends to , so .
- (v)
-
Target C ().Then and , so and , hence .
- (vi)
-
Target B ( ). Defineand setThen and with , so .
- (vii)
-
Target A ().Then and , so and ; hence .
- For , for any n.
- For , .
- For , .
- For , .
- For , .
- For , .
- For , .
- Thus if , then the corresponding codes coincide: . Since is injective, implies . Hence each is a one-to-one map.
3.2.2. Microscale
- Case (finite limit). By definitionGiven any , choose the constant connector . Then for all n, so is the constant zero sequence and hencethat is, . Since a was arbitrary, we obtain for every . Restricting to distinct blocks, all six implications with are true.
- Case (). Herewe need the product to diverge to .
- Positive result. If , then , so eventually. With the constant connector we have , and thereforeso for every . Thus .
- Negative results. By Lemma 2.11, if a sequence has infinitely many zeros then no Hadamard product with it can belong to F (its liminf and limsup cannot both be ). Hence, if a block X contains even one sequence with infinitely many zeros, then : taking that particular witnesses the failure of the definition of .
- in A: for odd n, for even n. Then , , and a has infinitely many zeros;
- in B: for even n, for odd n, so , ;
- in C: for odd n, for even n, so , ;
- in D: for example , , (), so , ;
- in G: the constant zero sequence has .
- In each case a has infinitely many zeros, so by Lemma 2.11 no connector c can produce . Thus
- Case (). This is completely symmetric to the previous case. We have
- Positive result. If (so ), the connector gives , henceand so for every . Thus .
- Negative results. We reuse exactly the same “infinitely many zeros’’ witnesses in listed above. For each such a no Hadamard product can have , again by Lemma 2.11. Consequently,
- Case (, ). HereBy the D–pattern in Lemma 2.12, for every with we can construct a connector c such that satisfieshence . Therefore,
- Case (). NowUsing the C–pattern in Lemma 2.12, we can, for every with , construct a connector c such thatso that . Hence
- Case (finite ). We haveBy the B–pattern of Lemma 2.12, for each with we can construct a connector c so that, for instance,and hence . Thus
- Case (, finite). Finally,Using the A–pattern in Lemma 2.12, we can, for every with , build a connector c such thatso that . ThereforeRestricting to distinct blocks, this yields for all .
-
Step 2: Summary of Cases Summarizing all implications, the adjacency matrix (rows = source X, columns = target Y) for distinctive pairs isand concretely:□
4. Discussion
4.1. Summary & Contributions
4.2. Comparison of Macroscale Matrix U versus Microscale Matrix V
4.3. Limitations & Future Work
4.4. Conclusions
Funding
Institutional Review Board Statement
Informed Consent Statement
Data Availability Statement
Acknowledgments
Conflicts of Interest
Abbreviations
- c: cardinality of the continuum; HamSim: Hamming similarity; JacSim: Jaccard similarity; lim inf: limit inferior; lim sup: limit superior; N: set of natural numbers; R: set of real numbers; Seq(R): sequence space.
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| # | Block | Definition of | Representative sequence | Size |
| 1 | A | continuum | ||
| 2 | B | continuum | ||
| 3 | C | continuum | ||
| 4 | D | continuum | ||
| 5 | E | continuum | ||
| 6 | F | continuum | ||
| 7 | G | continuum |
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