4. Ranked Soft Groups Homomorphism and Normalistic Ranked Soft Groups
In this section, we extend the classical notion of group homomorphisms to the ranked soft setting by introducing the concept of ranked soft group homomorphisms. These mappings preserve both the algebraic structure of groups and the layered soft information associated with ranked parameters. Such homomorphisms allow us to study how ranked soft groups relate to one another under structure-preserving transformations, enabling a deeper analysis of their morphic behavior and categorical properties.
Additionally, we have investigated a special class of ranked soft groups, namely normalistic ranked soft groups, where each soft component is a normal subgroup of the base group. These structures inherit symmetry properties from their classical counterparts and are central to understanding kernel-like structures and quotient-like constructions within the ranked soft context.
Together, the study of homomorphisms and normalistic ranked soft groups forms a foundation for exploring advanced algebraic operations and relationships in ranked soft group theory. This section introduces formal definitions, key properties, and fundamental results related to these concepts.
Definition 4.1. Let be a ranked soft group over a group , and be a ranked soft group over a group . A triple is called a ranked soft group homomorphism from to if:
is a group homomorphism,
is a mapping between parameter sets,
is a function satisfying for all ,
For all , .
Let be a ranked soft group over a group . A sub-ranked soft group of is called a ranked soft normal subgroup (RSNS) of if for every , is a normal subgroup of , i.e., . Equivalently, for all and .
Definition 4.2. Let be a ranked soft group over a group . Then is called a normalistic ranked soft group (NRSG) over if , where ⊴ stands for normal subgroup.
Theorem 4.1. Let be a group, and let be a NRSG over . Let and define (the restriction of r to B). If is non-null, i.e., there exists such that , then is also a normalistic ranked soft group over .
proof: Since is a normalistic ranked soft group, we have: .
Let and define . Suppose that is non-null, i.e., there exists such that . Then:
.
Since (as ), and this holds for all , we conclude that: .
Hence, satisfies the definition of a normalistic ranked soft group.
In other words the statement of the theorem can be illestrated as: be a normalistic ranked soft group NRSG over a group , and let . Then the restriction is also a normalistic ranked soft group over , provided that is non-null, i.e., there exists some such that .
Definition 4.3. Let and be normalistic ranked soft groups over the groups and , respectively. Define their product as the triple over the group , where:
for all ,
.
Then is called the product ranked soft group of and .
If each and , then , so the product we can see in the next theorem is also a normalistic ranked soft group.
Theorem 4.2. Let and be two normalistic ranked soft groups over the groups and , respectively.
Define their product as over , where:
for all ,
.
If the product soft set is non-null, i.e., there exists such that and , then is a normalistic ranked soft group over .
Proof: Let and be normalistic ranked soft groups over groups and , respectively.
This means that for all and , we have: .
Define a new soft set on the Cartesian product by .
Also define the ranking function by .
Now suppose the product soft set is non-null, i.e., there exists some such that and . Then the support of the product soft set is: .
We now show that is a normal subgroup of for each .
Since and (by normalistic property of the original soft groups), it is a well-known group-theoretic fact that: .
Hence, satisfies:
for all in its support,
is a well-defined ranking function.
Therefore, is a normalistic ranked soft group over .
Theorem 4.3. Let be normalistic ranked soft groups over groups for . Then the product is associative up to isomorphism: as normalistic ranked soft groups over .
Proof: We define the product of normalistic ranked soft groups component-wise, both in terms of soft sets and ranking functions.
Let , , and be N-RSGs over , , and , respectively.
Define:
Let us construct both group structures:
LHS:
RHS:
We define a bijection between the index sets: This map is a natural isomorphism of sets, and similarly, the group isomorphism: is a well-known group isomorphism (since direct product is associative up to isomorphism). Now consider the soft set: , and on the RHS: . But these are isomorphic subgroups of under the group isomorphism . Furthermore, the ranking functions are: , . So under . Hence, the two ranked soft structures are isomorphic via the natural isomorphisms on groups and parameter spaces. Since each is normal in , their products are normal in the group products, and thus both structures define normalistic RSGs over the same group.
Theorem 4.4. Let be a normalistic ranked soft group over a group , and let be a group homomorphism. Define a new soft set by . Then the triple is a normalistic ranked soft group over .
Proof: Since is a normalistic ranked soft group over , by definition, for every , we have: . That is, is a normal subgroup of for all such a. Let be a group homomorphism. Then it is a standard result in group theory that the image of a normal subgroup under a group homomorphism is a subgroup of the image, but not necessarily a normal subgroup in general. However, if is surjective, then is a normal subgroup of . To ensure that defines a normalistic ranked soft group over , we assume that is a surjective group homomorphism. Under this assumption, for each : . Thus, for each , is a normal subgroup of . The ranking function remains unchanged and is well-defined. Therefore, is a normalistic ranked soft group over .
Theorem 4.5. Let and be ranked soft groups over the groups and , respectively, and let be a group homomorphism. Suppose that for each , and . Define the kernel soft set by: , where is the identity in . Then the triple is a normalistic ranked soft group over .
Proof: Let be a ranked soft group over . For each , is a subgroup of . Let be a group homomorphism and define . We claim that for each , is a normal subgroup of . Since is a group homomorphism, the kernel of is a normal subgroup of . Also, the intersection of a subgroup with a normal subgroup is a subgroup. Note that: , where denotes the kernel of the homomorphism as a subgroup of . Since:
(because is a soft group),
(standard group theory),
the intersection of a subgroup and a normal subgroup is a subgroup (not necessarily normal),
it follows that is a subgroup of . To show that , we assume that is not only a subgroup but is normal in (i.e., is a normalistic ranked soft group). Then: is the intersection of two normal subgroups of , and thus is itself a normal subgroup: . Hence, for each , is a normal subgroup of . The ranking function remains unchanged from the original ranked soft group. Therefore, the triple is a normalistic ranked soft group over .
Theorem 4.6. Let be a group, and let be a fixed normal subgroup of . Let A be a nonempty set of parameters, and let be defined by . Let be any ranking function. Then the triple is a normalistic ranked soft group over .
Proof: By the definition of the soft set F, for each , we have: , where is a fixed normal subgroup of . Therefore, for every : . This directly satisfies the condition for a normalistic ranked soft group, which requires that for all , the value must be a normal subgroup of . Since for all , we have . The ranking function is arbitrary but valid, and assigns a real-valued rank to each parameter . Hence, the triple satisfies all the conditions of a normalistic ranked soft group:
Therefore, is a normalistic ranked soft group over .