3. Level Index and Dendrimer Graphs
In a rooted tree, a vertex
determined as a root or central vertex. The distance
from the central vertex is
denoted by [2].
This
distance (measured with edges) is called by level. The distance from the root
to a vertex with the highest level is called height of the tree [2]
.
Balaji and Mahmoud introduced two
distance based topological indices for rooted trees [2]
.
The first one is called level index and
level index of a tree is denoted by
. Level index of a tree
is computed by the following
equation
such that
and
showing the vertices at distances
and
from the central vertex of the
tree
.
In order to exemplify the level
index, we use the example given in the paper [2].
Figure 1.
The tree which is used in the following
example.
Figure 1.
The tree which is used in the following
example.
Example 3.1.
The level index of
is computed by
Now we can describe a level
counting polynomial which is called level polynomial of the graphs.
Definition 3.2.
The level polynomial of a rooted tree
is given by
where
shows the number of vertex pairs
having level difference
. It is understood that level
index of a graph
equals to
Lemma 3.3.
For a given dendrimer graph
(depicted in Figure 2) with central vertex
, the following properties are
hold [11]
The order of
is
,
contains
branches,
Every branch of
contains
vertices,
Every branch of
contains
leaves,
Every branch of
contains
non-leaf vertices,
There are
vertices at distance
from
.
Figure 2.
Dendrimers and
.
Figure 2.
Dendrimers and
.
4. Main Results
In this section we obtain the main
results of the paper. We obtain the level polynomial of some classes of
graphs. If
denotes the number of vertices on
level
, we can show the level
polynomials of rooted trees as in the following theorem. Even though there
exists one vertex at first level (a0 = 1) in a rooted tree, the definition
of level polynomial can be extended to other graphs and
can take different values in the
future.
Theorem 4.1.
The level polynomial of a rooted tree
is obtained by the following
equation such that the number of vertices on level
is denoted by
Proof.
If the height of a rooted tree is showed by
,
the
exponents of
changes
from
to
. Since the level polynomial of a
rooted tree can be presented as
The main problem is finding the
coefficients of the level polynomial of
. Since a level has to be greater
than 1, there is no constant term in the level polynomial.
The coefficient of
is
, because the vertex pairs which
have level difference
are located on level 0 and level
. Similarly The coefficient of
is,
because the vertex pairs which
have level difference
are located on levels
and levels
.
By this way we obtain the
coefficient of
as
, because we want to obtain the
number of vertices which have level difference 2.
Finally the coefficient of
is
. Because the vertices which have
level difference 1 are located at consecutive levels. It means that the level
polynomial of a rooted tree
is presented as follows
Remark 4.2.
The level index of a rooted tree equals to following equation by
Defnition 3.2
We can find the level polynomials
of trees which represent the triangular numbers as in the following figure.
Let
be a tree which has
vertices on the level
(depicted in
Figure 3 for
). It means that there is a
central vetrex, two vertices on first level, three vertices on the second level
and
vertices on
-th level (triangular numbers).
The sum of coefficient of level polynomial of
gives a new application of the
integer sequence A000914 from OEIS.
Theorem 4.3.
Assume that
is defined above. Then its level
polynomial is defined as follows
Proof.
For a given sequence
, the level partitions are defined
as in the following phrases,
By these phrases for a given level
, the coefficients are ordered. Then
the level polynomial of
is presented as in the following
equation
Let
be as in the previous theorem.
Now it is denoted the sum of coefficients of level polynomials by
such that
Theorem 4.4.
For a positive integer
, the number of
is computed as in the following
equation
Proof.
In order to find the level number of a positive integer
, we use Therorem 4.3 in obtaining
the sum of coefficients of Level polynomials of the tree
.
Now we obtain the initial terms of
the sequence of
. For a positive integer
, there is a tree
which has levels and there are
vertices on level
(
. By this way initial terms are
obtained as
Theorem 4.5.
The level index of the tree
is defined in the following
equation
Proof.
In order to find the level index of a positive integer
, we use Remark 4.2 in obtaining
the sum of coefficients of Level polynomials of the tree
.
Since the level polynomial of
is given in the Theorem 4.2
If we obtain the initial terms of
the sequence which is obtained in the Theorem 4.5
This sequence is appeared in the
OEIS with reference number A067056 for level index of greater than 1.
Theorem 4.6.
Let
be a tree with level
. Assume that
is a tree which is obtained from
by attaching a new vertex
to
-th level of
. Then the difference between the
level polynomials of
and
is
Proof.
Assume that a vertex
is attached the
-th level of
. Then difference between the
level polynomials of
and
is
with the open form. We can write
this equaion by
By the last equation, we can
compute the difference of level indices of
and
.
Theorem 4.7.
Let
be a rooted tree. Then the level
polynomial of
equals to Hosoya polynomial
if and only if
.
Proof.
Since a path
has one vertex at each level,
there exists one vertex for each distance from
. Then the level polynomais of
equals to Hosoya polynomial of
as in the following equation
Since the polynomials equal, we
obtain that
Now we assume that
. It means that
and there are at least two
vertices at a level. Let such a level be
-th level and two vertices
and
be two vertices at this level.
Therefore,
and
are at the same level and the
difference of level equals to zero but the distance between
and
is two. For the vertices which
are located at the levels greater than
, distances from
equal to level difference plus
two. Then the Hosoya polynomial of
is greater than Level polynomial
of
as in the following equation.
If the number of vertices which
are the same level increases, then the difference
also increases.
Theorem 4.8.
The level polynomial of a star
of order
equals to following equation
Proof.
The star graph
Sn
is
consisted of a root and
leaves at distance one from the
root. Then we obtain the level polynomial and level index of
as follows
Let
be a caterpillar graph which is
defined in
.
is obtained from a path
by attaching leaves to vertices
of paths as the leaves located at consecutive level. It means that
is root, at level
for
there are
vertices, and at the level
there are
leaves. To easify the notation
we can write
instead of
.
Theorem 4.9.
The level polynomial of a caterpillar graph
equals to
Proof. The distance
can be obtained between the root
and
Then we can write the level
polynomial of
caterpillar graph
We compute the level index of
caterpillar
as in the following equation
The last equation equals to level
index of caterpillar which is obtained by direct calculation in the paper
.
Corollary 4.10.
If it is taken
,
the
level polynomial and level index of a caterpillar graph
are given in the following
equations
Corollary 4.11.
If it is taken as
, the following equations are
obtained
Corollary 4.12. If it is taken
, the level polynomial and level
index of a caterpillar graph
are given in the following
equations
Theorem 4.13.
The level polynomial of tree
of order
is computed by the following equation
Proof.
The tree
is consisted a central vertex
v and
paths
which are attached to
(see
Figure 4). It means that
.
The level index of
can be computed from the first
derivative of
.
By this equation we obtain the
level index of
as in the following equation.
Theorem 4.14.
The level polynomial of dendrimer (depicted in Figure 2) graph
of order
is computed by the following
equation
Proof.
We use Theorem 4.1 for the level polynomial of dendrimer graph
If the previous equation is
written in a closed form, we obtain that
To compute the level index of
dendrimer graph
, we can take the first derivative
of level polynom of
.
This equation can be restated as
follows.
The first term and second term of
are showed by the following
equation.
The third term of the
is restated by the following equations
We can take
for easy writing of the equations. By this way we obtain the equation
as in the short equation
The third term of the
can be written as follows
such that
It follows from the fact that the coefficients of are symmetric around , and from the fact that the coefficients of odd powers sum to squares and of even powers to twice the triangular numbers.
The first ten coefficients of are 1, 2, 4, 6, 9, 12, 16, 20, 25, 30 which are the first terms of an interesting integer sequence which is appeared in OEIS by reference number A002620.
Finally the level index of the dendrimer graph
equals to