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Proof of the Binary Goldbach Conjecture

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24 April 2025

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25 April 2025

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Abstract
In this article the proof of the binary Goldbach conjecture is established (Any integer greater than one is the mean arithmetic of two positive primes) . To this end the weak Chen conjecture is proved (Any even integer greater than One is the difference of two positive primes) and a " located " algorithm is developed for the construction of two recurrent sequences of primes ( and ( ), (( ) dependent of ( )) such that for each integer n their sum is equal to 2n . To form this a third sequence of primes ( ) is defined for any integer n by = Sup (p : p ≤ 2n - 3) , being the infinite set of positive primes. The Goldbach conjecture has been proved for all even integers 2n between 4 and 4. In the table of terms of Goldbach sequences given in Appendix 12 values of the order of 2n = are reached. An analogous proof by recurrence « finite ascent and descent method » is developed and a majorization of by 0.7 (2n) is justified.. In addition, the Lagrange-Lemoine-Levy conjecture and its generalization called ’’ Bezout-Goldbach ’’ conjecture are proven by the same type of algorithm.
Keywords: 
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1. Overview

Number theory " the queen of mathematics " studies the structures and properties defined on integers and primes (Euclid [13], Hadamard [15], Hardy and Wright [16], Landau [22], Tchebychev [35]). Numerous problems have been raised and conjectures made, the statements of which are often simple but very difficult to prove. These main components include
Elementary arithmetic . Determination and properties of primes, operations on integers
(basic operations, congruence, gcd, lcm, ).
Decomposition of integers into products or sums of primes
(fundamental theorem of arithmetic, decomposition of large numbers, cryptography and Goldbach's conjecture).
Analytical number theory . Distribution of primes (Prime Number Theorem,
Hadamard [15], De la Vallée-Poussin [36], Littlewood [25] and Erdos [12], the Riemann hypothesis,.....).
Gaps between consecutive primes (Bombieri,Davenport [3], Cramer [8], Baker,Harmann,Iwaniec, Pintz [4],[5],[20], Granville [14], Maynard [27], Tao [34], Shanks [30], Tchebychev [35] and Zhang [39]).
● Algebraic, probabilistic, combinatorial and algorithmic number theories . Modular arithmetic,
diophantine approximations, equations, arithmetic functions and algebraic, diophantine and
number geometry.

2. Definitions Notations and Background

The integers n, k, p, q, r,……..... used in this article are always positive.(2.1)
The symbol ‘‘ / ‘’ means " in relation to". (2.2)
Let P   be the infinite set of positive primes p k   (called simply primes) (2.3)
( p 1 = 2 ; p 2 = 3 ; p 3 = 5 ; p 4 = 7 ; p 5 = 11 ; p 6 = 13 ; .........)
For any integer K ≥ 1 P K = { p P : p ≤ 2K } (2.4)
The writing of large numbers (see appendix 12) is simplified using the following constants
M = 10 9 ; R = 4. 10 8 ; G = 10 100 ; S = 10 500 ; T = 10 1000 (2.5)
ln(x) denotes the neperian logarithm of the real x > 0
Let (   W 2 n ) be the sequence of primes defined by
∀ n ∈ ℕ + 3 W 2 n = Sup(p ∈ P : p ≤ 2n - 3) (2.6)
Any sequence denoted by (   G 2 n ) = (   U 2 n ; V 2 n   ) verifying (2.6.1) is called a Goldbach sequence.
∀ n ∈ ℕ + 2 U 2 n , V 2 n P and U 2 n + V 2 n = 2n(2.7)
  U 2 n and V 2 n are also known as " Goldbach decomponents ".
Iwaniec,Pintz [20] have shown that for a sufficiently large integer n there is always a prime
between n − n 23 / 42   and n . Baker,Harman [4],[5] concluded that there is a prime in the interval
[ n ; n + o ( n 0.525 ) ]   . Thus this results provides an increase of the gap between two consecutive primes p k   and p k + 1     of the form
  ε > 0   k ε N * / ∀ k ∈ ℕ k ≥ k ε p k + 1 - p k < ε . p k 0.525 (2.8)
The results obtained on the Cramer-Granville-Maier-Nicely conjecture [1],[3],[8],[14],[26],[28] imply the following majorization.
For any real c > 2 and for any integer k ≥ 500
p k + 1 - p k ≤ 0.7 l n c ( p k ) (with probability one) (2.9)

3. Introduction

Chen [6], Hardy,Littlewood [17], Hegfollt,Platt [18], Ramaré,Saouter [29], Tao [34],
Tchebychev [35] and Vinogradov [37] have taken important steps and obtained promising results on the Goldbach conjecture (Any integer n ≥ 2 is the mean arithmetic of two primes).
Indeed, Helfgott,Platt [18] proved the weak Goldbach conjecture in 2013.
Silva,Herzog,Pardi [32] held the record for calculating the terms of Goldbach sequences after determining pairs of primes ( U 2 n   ;   V 2 n ) verifying
n ∈ ℕ / 4 ≤ 2n ≤ 4.1018  U 2 n + V 2 n = 2n (3.1)
In previous research work there is no explicit construction of recurrent Goldbach sequences. In this article two sequences of primes are developed using a simple, efficient and « located » algorithm to compute for any integer n 3 by successive iterations any term U 2 n and V 2 n .
Using Maxima scientific software on a personal computer Silva's record is broken and
the values 2n = 10500 and even 2n = 101000 are reached. The binary Goldbach conjecture can be established on the same principle by recurrence by using the weak Chen or Goldbach(-) conjecture
(any even integer greater than three is the difference of two primes) demonstrated in Teorem 4.
● Remark.
1. Chen conjecture: For any integer K ≥ 1 there are infinitely many pairs of primes with a difference equal to 2K.
2. Polignac conjecture : Same as Chen, but with consecutive pairs of primes.
3.What we know :
April 2013, Yitang Zhang [39] demonstrates that the smallest even integer 2K verifying
the conjecture is greater than 70 million.
In 2014, James Maynard [27] then Terence Tao [34] lowered this limit to 246.
We validate weak Chen or Goldbach(-) conjecture by verifying directly in the prime number tables that all even gaps from 2 to 246 are possible between primes.
In addition, the Lagrange-Lemoine-Lévy conjectures [9],[19],[21],[26],[28],[33],[38] and its generalization called ‘’ Bezout-Goldbach « conjecture’ are validated.
Using case disjunction reasoning we construct two recurrent sequences of primes (   V 2 n   ) and (   U 2 n   )
according to the sequence ( W 2 n ) by the following process
For any integer n ≥ 2
U 4 = 2 and V 4   = 2 (3.2)
Let n ∈ ℕ + 3
● Either
(2n - W 2 n ) is a prime
then V 2 n and U 2 n are defined directly in terms of W 2 n .
● Either
(2n - W 2 n ) is a composite number
then V 2 n and U 2 n are determined from the previous terms of the sequence (   G 2 n ) .

4. Theorem (Weak Chen or Goldbach(-) conjecture)

∀ K ∈ ℕ* p , q ∈ P /
p - q = 2K3 ≤ q ≤ 2K and 3 + 2K ≤ p ≤ 4K if K ≥ 2 (4.1)
Practical method on some examples:
First of all (5 - 3 = 2), then we begin the process at (7 - 3 = 4), we will select the smallest primes for which the difference is precisely 6 (11 - 5 = 6) then 8 (11 - 3 = 8)
then 10 (13 - 3 = 10),......... then 2K , then 2(K + 1) (demonstration established by strong recurrence, by the asurd and return).
All pairs of Goldbach(-) decomponents obtained by this method for K between 2 and 123 are listed in the table in Appendix 13.
Proof . The proof is established by strong recurrence on K . Let P C h e n   (K) be the following property
« ∀ K ∈ ℕ* p, q ∈ P / p - q = 2K3 ≤ q ≤ 2K and 2K + 3 ≤ p ≤ 4K «(4.2)
P C h e n (2) is true : 7 - 3 = 4 ; q = 3 ≤ 4 and p = 7 ≤ 4 x 2 = 8
Let’s show
M ∈ ℕ / MK then P C h e n (M)    P C (K + 1)
We reason through the absurd
p , q P K / pq ; ∀ h, m ∈ ℕ / p + 2h , q + 2m P we assume that
p + 2h - q - 2m ≠ 2(K + 1)
Therefore
p - q ≠ 2(K + 1 - h + m).
You can always choose (hm and h - mK + 1).
However the strong recurrence hypothesis asserts that
M ∈ ℕ / MK  p, q P / p - q = 2M(4.3)
By choosing M = K + 1 - h + m
t h i s c o n t r a d i c t s (4.3).
So
 h,m ∈ ℕ / p + 2h - q - 2m = 2(K + 1) (p, p+2h, q, q+2m P : hm and h - mK + 1) (4.4)
Thus validating the heredity of property P C h e n (K).
The property P C h e n (K) is therefore true. As a result Goldbach(-)’s conjecture is validated.

5. Corollary

Let ( R 2 K ) and ( Q 2 K ) two sequences of primes determined by
R 2 K = Inf (p ∈ P : p - 2K ∈ P ) and Q 2 K = Inf (p ∈ P : 2K + p ∈ P ) = R 2 K - 2K (5.1)
They are defined for any integer K ∈ N * and satisfy
(5.1) lim R 2 K = + (5.2) K N * R 2 K , Q 2 K P and R 2 K - Q 2 K = 2K
(5.3) For any integer K / 2 ≤ K ≤ 163 ≤ Q 2 K ≤ 2K and 2K + 3 ≤ R 2 K ≤ 4K
(5.4) For any integer K ≥ 16
3 ≤ Q 2 K ≤ 2 ( 2 K ) 0.525 and 2K + 3 ≤ R 2 K ≤ 2K + ( 2 K ) 0.525 Proof. According to the previous theorem, the sequences ( R 2 K   ) and ( Q 2 K   ) are defined by
strong recurrence and finite descent.
(5.1) R 2 K ≥ 2K ⇒ lim R 2 K = + (5.2) By construction, these sequences thus verify R 2 K - Q 2 K = 2K
(5.3) The term-to-term property can be verified directly by examining the sequence proposed above.
(5.4) This property is verified up to 2K = 246 by calculations on the previous list.
We prove this result by recurrence
First of all we order the Goldbach(-) decomponents at a fixed prime Q,
so as to obtain the estimate (5.4) more easily.
We examine the following sequences of primes (PQ(K)).
P3(K) = 2K + 3
(P3(K) ; 2K) → (5;2);(7;4);(11;8);(13;10);(17;14);(19;16);(23;20);(29;26);(29;28);..........
P5(K) = 2K + 5
(P5(K) ; 2K) → (7;2);(11;6);(13;8);(17;12);(19;14);(23;18);(29;24);(31;26);(37;32)........
P7(K) = 2K + 7
(P7(K) ; 2K) → (11;4);(13;6);(17;10);(19;12);(23;16);(29;22);(31;24);(37;30)...........
P11(K) = 2K + 11
(P11(K) ; 2K) → (13;2);(17;6);(19;8);(23;12);(29;18);(31;20);(37;26);(41;30);(43;34)......
(P13(K) ; 2K) → (17;4);(19;6);(23;10);(29;16);(31;18);(37;24);(41;28);(43;30);(47;34)......
PQ(K) = 2K + Q (K N * : PQ(K) and Q are primes)
(see the table in Appendix 14)
For any integer K satisfying 2 ( 2 K ) 0.525 > Q the property holds for PQ(K).
Therefore it is generally validated for all K > 15, since we obtain all possible cases of
Chen's weak conjecture starting with P3(K), then P5(K), then P7(K) ...... for 2 ( 2 K ) 0.525 Q .
(can be proved by strong recurrence using the same method as inTheorem 4 by “finite descent»).
Let c p = 40 21 and Pr(K) be the following property
« For any integer M < ( 0.5 Q K ) c p , there exists at least a prime Q < Q K such that
2 M + Q is a prime «
▶ Pr(15) is true (see Appendix 14).
▶ Let’s show : Pr(K) ⇒ Pr(K + 1)
Q K + 1 Q K + Q K 0.525 It is assumed thatM /
P K + 1 - Q K + 1 ≠ 2M M < ( 0.5 Q K + 1 ) c p P K + 1 = p + 2h and Q K + 1 = q +2s
then
p - q ≠ 2(M + s - h)
which is impossible according to the hypothesis of strong recurrence since
2(M + s - h) is less than ( 0.5 Q K   ) c p and that all primes p, q satisfy the recurrence hypothesis.
We deduce that Pr(K) ⇒ Pr(K + 1)
Thus the property (5.4) is true.

6. Principle of Proof

To determine pairs of primes that verify Goldbach’s conjecture three sequences of primes
( W 2 n ) , ( V 2 n ), ( U 2 n ) are defined and they verify the following properties
lim V 2 n = + . (6.1)
(6.2) ∀ n ∈ ℕ + 2 V 2 n   is defined as a function of W 2 n = Sup(pƤ : p ≤ 2n - 3)
(6.3) ( W 2 n ) is an increasing sequence of primes that contains all primes except p 1 = 2
(6.4) lim W 2 n = + (6.5) (   U 2 n   ) is a complementary sequence of negligible primes with respect to 2n
(6.6) For any integer n 3 ● If (2n - W 2 n ) is a prime
then V 2 n and U 2 n are defined by
(6.7) V 2 n = W 2 n and U 2 n = 2n - W 2 n ● Otherwise, if (2n - W 2 n ) is a composite number
we search for two previous terms of the sequence ( G 2 n ), U 2 ( n k ) ) and V 2 ( n k ) satisfying the following conditions
(6.8) U 2 ( n k ) , V 2 ( n k ) and U 2 ( n k ) + 2k are primes U 2 n k + V 2 n k = 2(n - k)
which is always possible (see Theorem 4)
So by setting
(6.9) V 2 n = V 2 ( n k ) and U 2 n = U 2 ( n k ) + 2k
two new primes V 2 n and U 2 n satisfying (4.10) are generated .
(6.10) U 2 n + V 2 n = 2n
This process is then repeated incrementing n by one unit (nn + 1).

7. Theorem

There exists a recurrent sequence ( G 2 n ) = ( U 2 n ; V 2 n ) of primes satisfying the following conditions.
For any integer n ≥ 2 U 2 n , V 2 n   ϵ   P and U 2 n + V 2 n = 2n(7.1)
(Any integer n ≥ 2 is the mean arithmetic of two primes)
An algorithm can be used to explicitly compute any term U 2 n and V 2 n . (7.2)
Proof .
□ FIRST METHOD :
For any integer n 3 ● If (2n - W 2 n ) is a prime
then V 2 n   and U 2 n are defined by
(7.3) V 2 n = W 2 n and U 2 n = 2n - W 2 n ● Otherwise, if (2n - W 2 n ) is a composite number
we use the previous terms of the sequence ( G 2 n   ).
For any integer q such that 1 ≤ qn - 3 we have
3 ≤ U 2 ( n q ) ≤ n .
Then, there exists an integer k / 1 ≤ kn - 3 following the Bertrand principle and Theorem 4
since all primes smaller than 2k are represented by U 2 ( n j ) , (if there were no such primes, we would have a contradiction with the Theorem 4 , even if it means transforming the indexing of the sequence (   U 2 n ) . In fact, in an equivalent way we can copy the proof of Teorem 4 by performing a similar strong recurrence “ finite descent return and absurd ” directly on the set { } U 2 ( r     j ) ).
such that
(7.4) R 2 n = U 2 ( n k ) + 2k ∈ Ƥ
The smallest integer k / R 2 n   Ƥ is denoted by k n .
So
(7.5) U 2 n = U 2 n k n + 2 k n and V 2 n = V 2 n k n (These two terms are primes)
In the previous steps two primes   U 2 n k n and V 2 n k n whose sum is equal to 2(n - k n ) were
determined.
(7.6) U 2 n k n + V 2 n k n = 2(n - k n )
By adding the term k n to each member of the equality (5.6), it follows
(7.7) U 2 n k n + 2 k n + V 2 n k n = 2(n - k n ) + 2 k n (7.8) [ U 2 n k n + 2 k n ] + V 2 n k n = 2n
(7.9) U 2 n + V 2 n = 2n
Finally for any integer n ≥ 3 this algorithm determines two sequences of primes ( U 2 n ) and ( V 2 n )
verifying Goldbach's conjecture.
□ SECOND METHOD :
The proof can be made using the following strong recurrence principle.
Let P(n) be the property defined for any integer n ≥ 2 by
P(n) : “ For any integer p satisfying 2 ≤ pn there exists two primes U 2 p and V 2 p such their sum is equal to 2p “ .
(∀ p ∈ ℕ / 2 ≤ p ≤ n U 2 p , V 2 p   ϵ   P and U 2 p + V 2 p = 2p)
Let's show by strong recurrence that P(n) is true for any integer n ≥ 2
a) P(2) is true : it suffices to choose U 4 = V 4 = 2 .
b) Let's show that the property P(n) is hereditary i.e ∀ k ∈ ℕ + 2P(n)   P (n+ 1)
Assume property P(n) is true,
● If (2(n + 1) -  W 2 ( n + 1 ) ) is a prime
then V 2 ( n + 1 )   and U 2 ( n + 1 )   are defined by
V 2 ( n + 1 ) = W 2 ( n + 1 ) and U 2 ( n + 1 ) = 2(n+1) - W 2 ( n + 1 ) (7.10)
● Otherwise, if (2(n+1) - W 2 ( n + 1 ) ) is a composite number
there exists an integer k to obtain two terms U 2 ( n + 1 k ) ) and V 2 ( n + 1 k ) satisfying the following
conditions
(7.11) U 2 ( n + 1 k ) , V 2 ( n + 1 k ) and U 2 ( n + 1 k ) + 2k are primes U 2 n + 1 k + V 2 n + 1 k = 2(n +1- k)
(which is always possible : see FIRST METHOD and Theorem 4).
Thus by setting
(7.12) V 2 ( n + 1 ) = V 2 ( n + 1 k ) and U 2 ( n + 1 ) = U 2 ( n + 1 k ) + 2k
Two new primes V 2 ( n + 1 ) and U 2 ( n + 1 ) satisfying (   U 2 ( n + 1 ) + V 2 ( n + 1 ) = 2(n + 1)) are generated.
It follows that P(n + 1) is true. Then the property P(n) is hereditary (P(n) => P(n + 1)).
Therefore for any integer n ≥ 2 the property P(n) is true.
it follows
 n ∈ ℕ+2there are two primes U 2 n and V 2 n and such their sum is 2n : ( U 2 n + V 2 n = 2n)

8. Lemma

The sequence ( U 2 n ) verifies the following majorization
For any integer n ≥ 65
(8.1) U 2 n ≤ (2 n ) 0.55 Proof . According to the programm 11.2 and appendix 12 the majorization (8.1) is verified
For any integer n such that 65 ≤ n ≤ 2000 . For any integer n > 2000 the proof is established by recurrence. For this purpose let P1(n) be the following property
(8.2) P1(n) : “ There exists a strictly increasing sequence of positive numbers ( C n ) such that
U 2 n C n ( 2 n ) 0.525 “ .
P1(2000) is true according to program 11.2 and the table in appendix 12.
For any integer n ≥ 2000 let’s show that P1(n) is hereditary i.e P1(n) ⇒ P1(n + 1).
Assume that P1(n) is true : then
● If (2(n + 1) - W 2 ( n + 1 ) ) is a prime
then V 2 ( n + 1 ) and U 2 ( n + 1 ) are defined by
(8.3) V 2 ( n + 1 ) = W 2 ( n + 1 ) and U 2 ( n + 1 )   = 2(n + 1) - W 2 ( n + 1 ) According to the results in [4],[5],[20] there is a constant K > 0 such that
(n + 1) - K . [ 2 ( n + 1 ) ] 0.525 < W 2 ( n + 1 ) < 2(n + 1)
U 2 ( n + 1 ) < K . [ 2 ( n + 1 ) ] 0.525 U 2 ( n + 1 ) C n + 1 . [ 2 ( n + 1 ) ] 0.525 ● Otherwise, if (2(n + 1) - W 2 ( n + 1 ) ) is a composite number
(8.4) p ∈ N * / U 2 ( n + 1 ) = U 2 ( n + 1 p ) + 2p
According to [4],[5],[18] the smallest integer p defined in (6.4) verifies
(8.5) 2p < K.[ U 2 ( n + 1 p ) ] 0.525 and U 2 ( n + 1 p ) < C n + 1 p . [ 2 ( n + 1 p ) ] 0.525 It follows
U 2 ( n + 1 ) < K . C n + 1 p 0.525 . [ 2 ( n + 1 p ) ] 0.275625 + C n + 1 p . [ 2 ( n + 1 p ) ] 0.525 Then
(8.6) U 2 ( n + 1 ) < C n + 1 . [ 2 ( n + 1 ) ] 0.525 and by setting C n = ( 2 n ) 0.025 It follows
(8.7) U 2 ( n + 1 ) < [ 2 ( n + 1 ) ] 0.55 P1(n + 1) is true then P1(n) is hereditary.
So for any integer n ≥ 2000 the property P1(n) is true.
(The inequality (6.7) is verified with the aid of the software Maple studying the functions of the type f : x  a  .   x 0.275625 + b . x 0.525 increased by g : x   x 0.55 a and b being two strictly positive real parameters).
Remark. A more precise estimate can be obtained using the Cipolla or Axler frames [7],[2].

9. Theorem

For any integer n 3 it is easy to check
(9.1) ( W 2 n ) is a positive increasing sequence of primes.
(9.2) { W 2 n : n IN + 3 } { 2 } = P (9.3) lim W 2 n = +oo
(9.4) ( U 2 n ) and ( V 2 n ) are sequences of primes and the set {( U 2 k ) : k n} contains all primes less than ln(n)
(9.5) n   V 2 n W 2 n (9.6) 3 2 n W 2 n U 2 n n
(9.7) lim V 2 n = +oo
Proof .
(9.1) For any integer n ≥ 2 P n P n + 1 .Therefore, W 2 n W 2 ( n + 1 ) . So the sequence ( W 2 n )
is increasing.
(9.2) Any prime except p 1 = 2 is odd, hence the result.
(9.3) lim W 2 n = lim p k = +oo
(9.4) By definition V 2 n = W 2 n or there exits an integer kn - 2 such that V 2 n = V 2 ( n k ) ;
so the terms of the sequence ( V 2 n ) ) are primes.
(9.5) According to Lemma 6, for any integer n ≥ 65
U 2 n < ( 2 n ) 0.55 therefore
U 2 n < ( 2 n ) 0.55 < n
and
V 2 n = 2n - U 2 n > 2n - n > n
For any integer n / 3 ≤ n ≤ 65 verification is carried out according to the computer program in paragraph 11.2 and the table in appendix 12.
we can also see that by construction V 2 n U 2 n because if we assume the opposite then V 2 n is not the largest prime number verifying 1 2 ( U 2 n + V 2 n ) = n .
So
V 2 n ≥ n
(9.6) According to (9.5) n   V 2 n U 2 n = 2n - V 2 n ≤ 2n - n ≤ n
therefore
V 2 n W 2 n ⇒ 2n - W 2 n ≤ 2n - V 2 n = U 2 n (9.7) By (9.5) for any integer n ≥ 2 : n   V 2 n so
lim V 2 n = +oo .

10. Remarks

10.1 For any integer k ≥ 2 there are infinitely many integers n such that U 2 n = p k .
10.2 V 2 n ~ 2n for (n +oo) .
10.3 For any sufficiently large integer n / n ≥ 5000
  U 2 n   V 2 n andlim ( U 2 n V 2 n ) = 0.
10.4 The smallest integer n such that
U 2 n   2n - W 2 n is obtained for n = 49 and G 98   = (79 ; 19).
(This type of terms increases in the Goldbach sequence ( G 2 n ) as n increases in the sense of the Schnirelmann density and there are an infinite number of them; their proportion per interval can be computed using the results given in [29]).
10.5 If q is an odd integer greater than four we could generalize this algorithm with sequences (   W ' 2 n   )
defined by
(10.5.1) n ∈ N / n ≥ ( q + 3 ) 2   W ' 2 n = Sup(p ∈ P : p ≤ 2n - q)
Other Goldbach’s sequences   G ' 2 n independent of (   G 2 n ) are thus generated.
10.6 The sequence ( G 2 n ) is ‘‘extremal’’ in the sense that for any integer n   2   V 2 n and U 2 n are the largest and smallest possible primes such that U 2 n + V 2 n = 2n.
10.7 The Cramer-Granville-Maier-Nicely conjecture [8],[14],[19],[21],[23],[24],[26],[28],[33]
is verified with probability one. It leads to the following majorization
For any integer p ≥ 500
(10.7.1) U 2 p ≤ 0.7 [ l n ( 2 p ) ] ( 2.2 1 p ) (with probability one)
The proof is similar to that of lemma 8 and is validated by the studying functions of the type
f : x a .g (x) + b [ l n ( g ( x ) ) ] c (a,b > 0 ; c > 2) with
g : x 0.7 [l n ( x ) ] ( c 1 x ) and h : x 0.7 [ l n ( x ) ] ( 2.2 1 x ) using Maple software.
Remark. A better estimate can be obtained via [26],[28],[30] .
10.8 According to Bombieri [3] and using the same method as in the proof of Lemma 8,
on average, we obtain the following estimate of U 2 n (10.8.1)   ε > 0 U 2 n = O ( l n 1.3 + ε ( 2 n )) (on average)

11. Algorithm

11.1. Algorithm Written in Natural Language

Inputs :
Input four integer variables : k, N, n, P
Input : p 1 = 2 , p 2 = 3 , p 3 = 5 , p 4 = 7 , ................., p N the first N primes.
: n = 3
: P = M, R, G, S or T as indicated in paragraph 2
Algorithm body :
Compute : W 2 n = Sup(p   P : p ≤ 2n - 3)
If T 2 n = (2n - W 2 n ) is a prime
Let :
(11.1.1) U 2 n = T 2 n and V 2 n = W 2 n otherwise
If   T 2 n is a composite number
Let : k = 1
B.1) While  U 2 n k + 2k is a composite number
assign to k the value k + 1 (k k + 1).
return to B1)
End while
Assign to k the value k n (k k n )
(11.1.2) Let :
U 2 n = U 2 n k n + 2 k n and V 2 n = V 2 n k n Assign to n the value n + 1 (n   n + 1 and return to A)
End :
Outputs for integers less than 10 4 : : Print (2n = ● ; 2n - 3 = ● ; W 2 n = ● ; T 2 n = ● ; V 2 n = ● ; U 2 n = ●)
Outputs for large integers :
Print (2n - P = ● ; 2n - 3 - P = ● ; W 2 n - P = ● ; T 2 n = ● ; V 2 n P = ; U 2 n = ●)

11.2. Program Written with Maxima Software for 2n = 10 500

n1 : 10**500 ; for n :5*10**499 + 10000 thru 5*10**499 + 10010 do
(a :2*n , c :a - 3 , test : 0 , b : prev_prime(a - 1) ,d :a - b ,
if primep(d)
then print(a - n1 , c - n1 , b - n1 , d , b - n1 , d)
else (
while test = 0 do
(e :a - c , if (primep(c) and primep(e))
then (test:1 , print(a - n1 , b - n1 , d , c - n1 , e ," ** "))
else (test : 0 , c : c - 2))) ;

12. Appendix

Application of Algorithm 11 : Table of U 2 n   and V 2 n   terms of the Goldbach sequence ( G 2 n ) computed from program 11.2 (2 ≤ 2n 10 1000 + 4020).
The ** sign in the table below indicates the results given by the algorithm 11 in case B) of return to the previous terms of the sequence ( G 2 n ) . WATCH OUT ! For large integers n (2n >   10 9 for example), to simplify the display of large numbers the results are entered as follows
2n - P , (2n - 3) - P , W 2 n - P , T 2 n , V 2 n - P and U 2 n with
P = M, R, G, S, orTconstants defined in (2.3)
Preprints 157168 i001
Preprints 157168 i002
Preprints 157168 i003
Preprints 157168 i004

13. Appendix

7-3=4 11-5=6 11-3=8 13-3=10 17-5=12 17-3=14 19-3=16 23-5=18
23-3=20 29-7=22 29-5=24 29-3=26 31-3=28 37-7=30 37-5=32 37-3=34
41-5=36 41-3=38 43-3=40 47-5=42 47-3=44 53-7=46 53-5=48 53-3=50
59-7=52 59-5=54 59-3=56 61-3=58 67-7=60 67-5=62 67-3=64 71-5=66
71-3=68 73-3=70 79-7=72 79-5=74 79-3=76 83-5=78 83-3=80 89-7=82
89-5=84 89-3=86 101-13=88 97-7=90 97-5=92 97-3=94 101-5=96 101-3=98
103-3=100 107-5=102 107-3=104 109-3=106 113-5=108 113-3=110 131-19=112 127-13=114
127-11=116 131-13=118 127-7=120 127-5=122 127-3=124 131-5=126 131-3=128 137-7=130
137-5=132 137-3=134 139-3=136 149-11=138 151-11=140 149-7=142 149-5=144 149-3=146
151-3=148 157-7=150 157-5=152 157-3=154 163-7=156 163-5=158 163-3=160 167-5=162
167-3=164 173-7=166 173-5=168 173-3=170 179-7=172 179-5=174 179-3=176 181-3=178
191-11=180 193-11=182 191-7=184 191-5=186 191-3=188 193-3=190 197-5=192 197-3=194
199-3=196 211-13=198 211-11=200 233-31=202 211-7=204 211-5=206 211-3=208 223-13=210
229-17=212 227-13=214 223-7=216 223-5=218 223-3=220 227-5=222 227-3=224 229-3=226
233-5=228 233-3=230 239-7=232 239-5=234 239-3=236 241-3=238 251-11=240 271-29=242
251-7=244 251-5=246

14. Appendix

(PQ(K) ; 2K)
Q= 3 Q= 5 Q= 7 Q= 11 Q= 13 Q= 17 Q= 19 Q= 23 Q= 29 Q= 31
5;2 7;2 13;2 19;2 31;2
7;4 11;4 17;4 23;4
11;6 13;6 17;6 19;6 23;6 29;6 37;6
11;8 13;8 19;8 31;8 37;8
13;10 23;10 29;10 41;10
17;12 19;12 23;12 29;12 31;12 41;12 43;12
17;14 19;14 31;14 37;14 43;14
19;16 23;16 29;16 47;16
23;18 29;18 31;18 37;18 41;18 47;18
23;20 31;20 37;20 43;20
29;22 41;22 53;22
29;24 31;24 37;24 41;24 43;24 47;24 53;24
29;26 31;26 37;26 43;26
31;28 41;28 47;28 59;28
37;30 41;30 43;30 47;30 53;30 59;30 61;30
37;32 43;32 61;32
37;34 41;34 47;34 53;34
41;36 43;36 47;36 53;36 59;36 67;36
41;38 43;38 61;38 67;38
43;40 47;40 53;40 59;40 71;40
47;42 53;42 59;42 61;42 71;42 73;42
47;44 61;44 67;44 73;44
53;46 59;46
53;48 59;48 61;48 67;48 71;48 79;48
53;50 61;50 67;50 73;50 79;50
59;52 71;52 83;52
59;54 61;54 67;54 71;54 73;54 83;54
59;56 61;56 67;56 73;56 79;56
61;58 71;58 89;58
67;60 71;60 73;60 79;60 83;60 89;60

15. Perspectives and Generalizations

15.1 Other Goldbach sequences ( G ' 2 n ) and ( G " 2 n ) independent of G 2 n may be studied using the increasing sequences of primes ( W ' 2 n ) ,   s e e   10 . 5   and (   W " 2 n   ) defined by
For any integer n 3 W " 2 n = Sup(p ϵ P : p f (n))
f is a function defined on the interval I = [3 ; + [ and satisfying the following conditions
f is strictly increasing on the interval I
f (3) = 3 and lim x + f ( x ) = + x ϵ I f x 2 x 3 For example, one of the following functions defined on I can be selected.
□ f : x a x + 3 - 3a(a R : 0 < a 2 ) g : x     [ 4 3 x 9 ] ([ x ] is the integer part of the real number x)
□ h : x 6 l n x 3 + 3
15.2 Using this method it would be interesting to study the Schnirelmann density [31] of primes
3 , 5 , 7, 11 ,........ ... in the sequence ( U 2 n   ) on variable intervals .
15.3 It is possible to exceed the values shown in the table of 2n = 10 1000   by perfecting this algorithm starting from n , exploiting the fact that one of Goldbach's decomponents can be chosen
equal to 12p + 1,
(the set of Goldbach decomponents consists of primes of the form 6p +/- 1) using Cipolla-Axler-Dusart type functions [2],[7],[10],[11] to better identify the terms of ( G 2 n   ) , u s i n g s u p e r c o m p u t e r s a n d m o r e e f f i c i e n t s s o f t w a r e a s Maple.
15.4 Diophantine equations and conjectures of the same nature (Lagrange-Lemoine-Levy conjecture [9],[19],[21],[23],[24],[33]) can be processed using similar reasoning and algorithms.
1) To validate the Lagrange_Lemoine-Levy conjecture we study the following sequences of primes
(W l 2 n ), (   V l 2 n )   a n d ( U l 2 n )   d e f i n e d b y F o r a n y i n t e g e r n 3 W l 2 n = Sup(p ϵ P : p n 1 ) ● If T l 2 n   = (2n + 1 - 2  W l 2 n ) is a prime
then let
V l 2 n = W l 2 n and U l 2 n = T l 2 n ● If T l 2 n is a composite number
then there exists an integer k / 1 k n 3   such hat
U l 2 n k + 2k is a prime
then let
V l 2 n = V l 2 n k and U l 2 n = U l 2 n k + 2k
Using the same type of reasoning a generalization called «Bezout-Goldbach conjecture» of the following form can be validated
● Let K and Q be two odd integers prime to each other :
For any integer n / 2n   3 (K + Q) there exist two primes U b 2 n and V b 2 n verifying
K . U b 2 n + Q. V b 2 n = 2n
● Let K and Q be two integers of different parity prime to each other :
For any integer n such that 2n 3 (K + Q) there are two primes U b 2 n and   V b 2 n verifying
K . U b 2 n + Q . V b 2 n = 2n + 1.
15.5 Remark
GOLDBACH(-) :
R 2 K = Inf (p ∈ P : p - 2K ∈ P ) and Q 2 K = Inf (p ∈ P : 2K + p ∈ P ) = R 2 K - 2K
GOLDBACH(+) :
V 2 K = Sup (p ∈ P : 2K - p ∈ P ) and U 2 K = Inf (p ∈ P : 2K - p ∈ P ) = 2K - V 2 K (Is it possible to envisage a symmetry in the Goldbach triangle parametrized by arithmetic sequences between the representations of primes and even integers ?)

16. Conclusions

16.1 A recurrent and explicit Goldbach sequence ( G 2 n ) = ( U 2 n   ; V 2 n ) verifying
n ∈ N + 2 U 2 n and V 2 n are primes a n d U 2 n + V 2 n = 2n
has been developed using an simple and efficient "located" algorithm.
16.2 The record of Silva [29] is beaten on a personal computer and ten Goldbach decomponents
U 2 n and V 2 n   are obtained for values of the order 2n =   10 1000   for a computation time of less than
three hours.
16.3 For a given integer n ≥ 49 the evaluation of the terms U 2 n and V 2 n does not require the computing of all previous terms U 2 k and V 2 k  / 1   k < n - 1 . We just need to know the primes p l and V 2 r   such that
(16.3.1) p l 7. l n 1.3 ( 2 n ) and 2n - 7. l n 1.3 (2n) ≤ V 2 r   ≤ 2n (on average)
This property allows quick computing of U 2 n and V 2 n .
16.4 Therefore the Lagrange-Lemoine-Levy and the binary Goldbach(- & +) conjectures,
« Any even integer greater than three is the sum and difference of two primes » are true.
In fact, these two conjectures are intertwined.

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