2. Ramsey Graphs Generated by Vector Fields
Consider vector field defined on
. Consider sets of six points
and six vectors related to these points
depicted in
Figure 1. Uppercase letters denote the coordinates of the points in
Origin of the vectors
is related to the points
) (actually, the vectors are seen as sliding ones, and the location of their origin is not important);
; lowercase letters denote the coordinates of the vectors (again, seen as sliding vectors). We define the set
as the set of vectors generating the complete bi-colored graph. Vectors
we denote as the “generators” of the Ramsey graph. The graph is built according to the following procedure. Points
serve as the vertices of the graph.
Vertices numbered i and j are connected with the red link, when Equation 1 takes place:
(1)
And, correspondingly, the vertices numbered i and j are connected with the green link, when Equation (2) occurs:
(2)
It is easily seen, that the exact location of the vectors/generators is not important, when the coloring procedure defined by Equations (1) and (2) is adopted. Vectors/generators themselves may be considered as the vertices of the graph. Vectors are “acquainted” each with another and they are connected with the red link, when Equation (1) takes place, and vectors are “not acquainted” each with another, and they are connected with the green link, when Equation (2) is true. The aforementioned procedure gives rise to the complete, bi-colored, Ramsey graph. Consider that the scalar product of vectors is independent of the system of coordinates; thus, the suggested coloring procedure defined by Equations (1) and (2) is invariant relatively to rotation/translations of frames.
Let us illustrate the introduced procedure with
Figure 2, demonstrating two vectors
and
, belonging to the same plane. Sketch
A depicts the situation, where points “1” and “2” are connected with the red link, i.e.,
takes place; whereas, sketch
B depicts the situation, where points “1” and “2” are connected with the green link, i.e.,
takes place
The aforementioned mathematical procedure gives rise to the bi-colored, complete, Ramsey graph, such as that depicted in
Figure 3, supplied as an example.
According to the Ramsey theorem, this graph should necessarily contain at least one monochromatic (mono-colored triangle); due to the:
. Indeed, we recognize in
Figure 3 the green subgraph, labeled “345”; whereas, the triangles “123”, “124”,”125”, “126”, “136”, “146” ,”156”, “236”, “246” and “256” are monochromatic red ones.
It should be emphasized that the introduced procedures of coloring, defined by Equations (1) and (2) are not transitive. In other words, if:
and
is assumed, it is not necessarily that:
. Let us illustrate this. Consider the planar system of vectors
, depicted in
Figure 4. Angles
are shown in
Figure 4. We adopt
, however
. Thus,
and
takes place. However,
is true (see
Figure 4). Thus, the introduced procedure of coloring of the graph edges is not transitive. The green-colored relation between the vectors/generators is also non-transitive; namely, if:
and
is assumed, it is not necessarily that:
This is important, due to the fact that the transitive Ramsey numbers are different from the non-transitive ones [
8,
9]. The situation is changed for 1D systems of vectors and discussed below in
Section 6.
It is also should be stressed, that only directions of the generating vectors are important; the generating vectors may be considered as the unit ones. We finally come to following theorem.
Theorem: Consider set of the six vectors defined on Vectors are taken as the vertices of the graph. Vertices are connected with the red link, if: takes place, and they are connected with the green link if: The graph contains at least one monochromatic triangle.
Assume, that actually we revealed the red triangle, built of the vertices numbered i, k and l. Thus, according to Equation (1) we have: ; and also . Hence, we derive for the “red” triangles: and also . The extension of this result for the “green” triangles is trivial.