Submitted:
28 June 2024
Posted:
28 June 2024
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Abstract
Keywords:
MSC: 34A08; 34A34; 34D20; 34N05
1. Introduction
2. Preliminaries, Definitions and Notations
- (i)
- if , t is right scattered,
- (ii)
- if , t is left scattered,
- (iii)
- if and , then t is called right dense,
- (iv)
- if and , then t is called left dense.
- (i)
- is true;
- (ii)
- If t is right scattered and is true, then is also true;
- (iii)
- For each right-dense t, there exists a neighbourhood such that whenever is true, is also true for all ,
- 1.
- is true is equivalent to the statement is true for
- 2.
- is true then is true is equivalent to if the statement is true for , then the statement is true for
3. Statement Of Problem
4. Inequalities on Fractional Dynamic Equations on Time scale and Comparison results
- (i)
- is true since
- (ii)
- (iii)
-
Let t be right dense and be a right neighborhood of . We need to show that is true for . This follows from the comparison theorem for Caputo fractional differential equations since at every right dense point , . See [1].Let be a small enough arbitrary positive number such that (where is a small enough number on the time scale ) and consider the initial value problemfor .The function is a solution of (23) if and only if it satisfies the delta Integral equationLet be such that , where is any other solution of (10). We show thatthe inequality (25) holds for sinceAssume that the inequality (25) is not true, then there exist a point such thatFrom lemma (1) it follows thatSo thatand using (23) we arrive atTherefore,Now,Since is locally Lipschtzian in the second variable, we haveWhere is a Lipschitz constant.As , so that from (19) we haveNow (27) with contradicts (26), hence (25) is true. For , we now show that whenever , thenNotice that (28) holds for since . Assume the inequality (28) is not true. Then there exist a point such that and for .By Lemma (1), we have thatHowever,which is a contradiction and so (28) is true. Now from (28) and since , we deduce thatand therefore we can say that the family of solutions is uniformly bounded with bound on . This means that for andWe now show that the family is equicontinuous on . Assume . Now let us take , as a decreasing sequence, such that and consider a sequence of functions and take with , then we have the following estimateA family of solutions is said to be equicontinuous if given , we can find such that whenever .implying that providedNow, we choose , but so since , then . Proving that the family of solutions is equi-continuous. By the Arzela-Ascoli theorem, has a sub-sequence which converges uniformly to a function on . We then show that is a solution of (11). Equation (24) becomesTaking the limit as , then on . Now (29) yieldsThus, is a solution of (11) on . Since exists, then for any that satisfies the dynamic equation (11), . So from (25), we have that on .Therefore by induction principle, the statement is true, and this completes the proof
- 1.
- the function , is locally Lipschitzian with respect to x, and the inequalityholds for all and
- 2.
- is nondecreasing with respect to u at all , , and
- 3.
- the zero solution of the comparison equation (11) is stable.
5. Application
6. Conclusion
Author Contributions
Funding
Institutional Review Board Statement
Data Availability Statement
Conflicts of Interest
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