Submitted:
23 March 2023
Posted:
24 March 2023
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Abstract
Keywords:
1. Introduction
2. Splitting Method
2.1. Numerical algorithm description
2.2. Splitting Error Analysis
3. Test Problem
4. Results and Discussions
- compute the numerical solutions on the following spatial meshes: 33 × 33, 65 × 65, 129 × 129 and 257 × 257, numbered by m = 1, 2, 3, 4;
- denote by Z(m-1) and Z(m) the solutions computed on the two consecutive meshes m – 1 and m, respectively; compute the difference between Z(m-1) and Z(m) by,where is the discrete p norm; the difference between Z(m-1) and Z(m) is computed for the common grid points;
- the spatial convergence rate is computed as,
- R(m)≈ 2 for all Pe values used in this work; this means second – order spatial accuracy for the present numerical solutions;
- the number of chemical species, n, does not affect the convergence rate;
- the values of , and the Stefan - Maxwell diffusion coefficients do not influence the convergence rate.
5. Conclusions
Appendix A.
Appendix B.
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| m | N | Err(m) | R(m) | ||||||
| Pe=1 | Pe=10 | Pe=102 | Pe=103 | Pe=1 | Pe=10 | Pe=102 | Pe=103 | ||
| 1 | 33 | - | - | - | - | - | - | - | - |
| 2 | 65 | 0.6×10-3 | 0.67×10-3 | 0.29×10-2 | 0.22×10-2 | - | - | - | - |
| 3 | 129 | 0.16×10-3 | 0.18×10-3 | 0.79×10-3 | 0.57×10-3 | 1.9 | 1.89 | 1.87 | 1.96 |
| 4 | 257 | 0.45×10-4 | 0.7×10-4 | 0.21×10-3 | 0.15×10-3 | 1.85 | 1.87 | 1.89 | 1.95 |
| m | N | Err(m) | R(m) | ||||||
| Pe=1 | Pe=10 | Pe=102 | Pe=103 | Pe=1 | Pe=10 | Pe=102 | Pe=103 | ||
| 1 | 33 | - | - | - | - | - | - | - | - |
| 2 | 65 | 0.14×10-2 | 0.16×10-2 | 0.68×10-2 | 0.82×10-2 | - | - | - | - |
| 3 | 129 | 0.36×10-3 | 0.42×10-3 | 0.18×10-2 | 0.21×10-2 | 1.97 | 1.96 | 1.95 | 1.95 |
| 4 | 257 | 0.93×10-4 | 0.11×10-3 | 0.46×10-3 | 0.56×10-3 | 1.96 | 1.95 | 1.95 | 1.93 |
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