Submitted:
21 February 2023
Posted:
22 February 2023
Read the latest preprint version here
Abstract
Keywords:
1. Background
2. Preliminaries
2.1. Motivation
2.2. Preliminary Definitions
- (1)
- (2)
- For all , exists (if A is countable infinite then for every , must be a finite set since is a discrete uniform distribution of ; otherwise, if A is uncountable, then is the normalized Lebesgue measure of or some other uniform measure on [6] where for every the Lebesgue measure or some uniform measure on exists and is finite. [1], p.32-37.
- (3)
- For all , is positive and finite where is intrinsic. (For countably infinite A, is the counting measure, and is positive and finite since is finite. For uncountable A, is the Lebesgue or radon-nikodym derivative on some uniform measures [6] where either of the measures on are positive or finite.)
- then is a pre-structure of A, since for every the sequence does not equal A, but “approaches" A as r increases.
- The element
- The set is arbitrary and uncountable.
- The element
- The set is arbitrary and uncountable.
- (1)
- Arrange the x-value of the points in the sample of uniform ε coverings from least to greatest. This is defined as:
- (2)
- Take the multi-set of the absolute differences between all consecutive pairs of elements in (1). This is defined as:
- (3)
- Normalize (2) into a probability distribution, where for multi-set X, we have as the cardinality of all elements in the multi-set, including repeated ones. This is defined as:
- (4)
- (a)
-
We take the cardinality of the sample of the uniform ε coverings of (def. 5) divided by the smallest cardinality of the sample of the uniform ε coverings of (def. 5), where the entropy on the sample of uniform coverings on (def. 6) is larger than the entropy on the sample of uniform coverings on (def. 6). In other words, if:then the ratio at the beginning of the paragraph is defined (using 7) as
- (b)
-
We take the cardinality of the sample of uniform ε covering of (def. 5) divided by the largest cardinality of the sample of the uniform ε covering of (def. 5), where the entropy on the sample of uniform coverings on (def. 6) is smaller then the entropy on the sample of uniform coverings on (def. 6). In other words if:then the ratio at the beginning of the paragraph is defined (using 9) as
- (1)
-
If using equations 8 and 10 we have that:we say converges uniformly to A at a superlinear rate to that of .
- (2)
-
If using equations 8 and 10 we have that:we say converges uniformly to A at a linear rate to that of .
- (3)
-
If using equations 8 and 10 we have that:we say converges uniformly to A at a sublinear rate to that of .
2.3. Question on Preliminary Definitions
- (1)
- Are there “simpler" alternatives to either of the preliminary definitions? (Keep this in mind as we continue reading forward).
3. Main Question
- (1)
- The expected value of f on each term of the pre-structure is finite
- (2)
- The pre-structure converges uniformly to A (def. 7)
- (3)
- The pre-structure converges uniformly to A at a linear or superlinear rate to that of other non-equivalent pre-structures of A (def. 9 & 10) which satisfy (1) and (2).
- (4)
- The generalized expected value [1] of f on a pre-structure satisfying (1), (2), and (3) (while the pre-structure converges uniformly to A) is finite (i.e. def. 3)
- (5)
- A choice function is defined which chooses a pre-structure satisfying (1), (2), (3), and (4) such the generalized expected value [1] is unique and finite for the largest subset of .
- (6)
- Out of all the choice functions which satisfy (1), (2), (3), (4) and (5), we choose the choice function with the “simplest form", (meaning for a general pre-structure of A, when each choice function is fully expanded, we take the choice function with the fewest variables/numbers (excluding those with quantifiers) for which the variables are added and exponentiated by infinitesimal amounts and multiplied by the difference of one and infinitesimal amount.
4. Informal Attempt to Answer Main Question
4.1. Choice Function
4.2. Questions on Choice Function
- (1)
-
What unique pre-structure would contain (if it exists) for:
- (a)
- where if , we want
- (b)
- where if , we want
- (c)
- where we’re not sure what would be in this case. What would be if it’s unique?
- (2)
-
There are a total of 113 variables in the choice function C (excluding quantifiers). Is there a choice function with fewer variables that answers criteria (1), (2), (3), (4) & (5) of the question in sec. 3 for a "larger" subset of ? (This might be impossible to answer since such a solution cannot be shown with prevalence or shyness [2,3]). Therefore, we need a more precise version of “size" with some examples (as shown in this answer [8]) being the following:
- (a)
- Fractal Dimension notions
- (b)
- Kolmogorov Entropy
- (c)
- Baire Category and Porosity
4.3. Generalized Expected Values
- (1)
- For a worst-case f defined on countably infinite A (e.g. countably infinite "pseudo-random points" non-uniformly scattered across the real plane), one might typically use (20) (since countable sets may need just one iteration of C for the generalized expected value to be unique); otherwise, one may use (21) for finite iterations of C.
- (2)
- For a worst-case f defined on uncountable A, we may have to use (22) as the function is so difficult to analyze. We can imagine this function as an uncountable number of "pseudo-random" points non-uniformly generated on a subset of the real plane (see 5.1 for a visualization.)
4.4. Questions Regarding The Answer
- (1)
-
Using prevalence and shyness [2,3], can we say the set of f where (20), (21), or (22) are unique and finite form either a prevalent or neither prevalent nor shy subset of . (If the subset is prevalent, this implies the generalized expected values are unique and finite for a “large" subset of ; however, if the subset is neither prevalent nor shy we need a more precise definition of “size" which takes “an exact probability that the expected values are unique & finite"—some examples (as shown in this answer [8]) being:
- (a)
- Fractal Dimension notions
- (b)
- Kolmogorov Entropy
- (c)
- Baire Category and Porosity
- (2)
- Can either (20), (21), or (22) (when A is the set of all Liouville numbers & ) give a finite value on the Liouville numbers? What would the value be?
- (3)
- Similar to how def. 11 approximates the expected value in def. 1, how do approximate (20), (21), and (22)?
- (4)
- Can we use programming to estimate (20), (21), and (22) (if a unique and finite results exists)?
4.5. Application
- (1)
-
In Quanta magazine [9], Wood writes on Feynman Path Integrals: “No known mathematical procedure can meaningfully average[2] an infinite number of objects covering an infinite expanse of space in general. The path integral is more of a physics philosophy than an exact mathematical recipe."—despite Wood’s statement, mathematicians Bottazzi E. and Eskew M. [10] found a constructive solution to the statement using integrals defined on filters over families of finite sets; however, the solution was not unique as one has to choose a value in a partially ordered ring of infinite and infinitesimal elements. In addition, although there were ways of preventing the use of the axiom of choice (within their integral), the axiom was still required for certain cases.
- (a)
- (2)
-
As stated in sec. 2.1, “when the uniform measure of A, measurable in the Caratheodory sense, has zero or infinite volume (or undefined measure), there may be multiple, conflicting ways of defining a "natural" uniform measure on A." This is an example of Bertand’s Paradox which shows, "the principle of indifference (that allows equal probability among all possible outcomes when no other information is given) may not produce definite, well-defined results for probabilities if applied uncritically when the domain of possibilities (i.e. sample space) is infinite [11].Using sec. 4.2, perhaps if we take:then for , if if we have the following:Then might serve as a solution to Bertand’s Paradox (unless there is a simpler solution to the main question in sec. 3).
- (a)
-
How do we apply (or a simpler solution) to the usual example which demonstrates the Bertand’s Paradox as follows: for an equilateral triangle (inscribed in a circle), suppose a chord of the circle is chosen at random—what is the probability that the chord is longer than a side of the triangle? [12] (According to Bertand’s Paradox there are three arguments which correctly use the principle of indifference yet give different solutions to this problem [12]:
- (i)
- The “random endpoints" method: Choose two random points on the circumference of the circle and draw the chord joining them. To calculate the probability in question imagine the triangle rotated so its vertex coincides with one of the chord endpoints. Observe that if the other chord endpoint lies on the arc between the endpoints of the triangle side opposite the first point, the chord is longer than a side of the triangle. The length of the arc is one-third of the circumference of the circle, therefore the probability that a random chord is longer than a side of the inscribed triangle is .
- (ii)
- The "random radial point" method: Choose a radius of the circle, choose a point on the radius, and construct the chord through this point and perpendicular to the radius. To calculate the probability in question imagine the triangle rotated so a side is perpendicular to the radius. The chord is longer than a side of the triangle if the chosen point is nearer the center of the circle than the point where the side of the triangle intersects the radius. The side of the triangle bisects the radius, therefore the probability a random chord is longer than a side of the inscribed triangle is .
- (iii)
- The "random midpoint" method: Choose a point anywhere within the circle and construct a chord with the chosen point as its midpoint. The chord is longer than a side of the inscribed triangle if the chosen point falls within a concentric circle of radius the radius of the larger circle. The area of the smaller circle is one-fourth the area of the larger circle, therefore the probability a random chord is longer than a side of the inscribed triangle is .
5. Glossary
5.1. Example of Case (2) of Worst Case Functions
5.2. Question Regarding Case (2) of The Worst Case Function
5.3. Approximating the Expected Value
- (1)
- We need to know when point x is in set A or not
- (2)
- We need to be able to generate points from a density g that is on a support that covers A but is not too much bigger than A
- (3)
- We have to be able to compute and for each point
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| [1] | The result of algebraic manipulation on the expected value in def. 3 that is unique and finite for the largest subset of . |
| [2] | Meaningful Average—The measure inside the average is canonical when the measure is normalized as a uniform probability measure [1], p. 32-37 |
| [3] | Wood wrote on Feynman Path Integrals: “No known mathematical procedure can meaningfully average [2] an infinite number of objects covering an infinite expanse of space in general. The path integral is more of a physics philosophy than an exact mathematical recipe." |
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